angelapeters said:
The speed of a moving sidewalk at an airport is 4ft/sec. A person can walk 97 ft forward on the moving sidewalk in the same time it takes to walk 4 ft on a non moving sidewalk in the opposite direction. At what rate would a person walk on a non moving sidewalk?
i) Pick a variable for the person's walking rate of speed.
ii) Note that his speed, relative to a bystander, on the moving sidewalk, is four feet per second greater than this. Use this information to create an expression, in terms of the variable in (i), for the sidewalk rate of movement.
iii) Since d = rt, then t = d/r. Use this relation to create an expression, in terms of (i) and the given non-moving-sidewalk (that is, pavement) walking distance, for the time "t" covered when walking on the pavement.
iv) Use the reasoning in (iii), along with the expression in (ii) and the given moving-sidewalk distance, for the time "t" covered when on the moving sidewalk.
v) Since the times are given as being equal, set the expressions in (iii) and (iv) equal to each other.
vi) Solve the equation in (v).
If you get stuck, please reply showing how far you got in following the instructions. Thank you!
Eliz.
