Word Problem Homework Help

You are given an equation and sets of domains. From those you are supposed to draw some conclusions.

What is the definition of speed that you have been taught?

Are you in Calculus yet?

What are your thoughts? Exactly where are you stuck?

Please follow the rules of posting in this forum, enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/

Please share your thoughts/work with us - so that we know where to begin to help you.
 
You are given an equation and sets of domains. From those you are supposed to draw some conclusions.

What are your thoughts? Exactly where are you stuck?

Please follow the rules of posting in this forum, enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/

Please share your thoughts/work with us - so that we know where to begin to help you.
I am confused on how I use the equation to find the cars average speed as the question specifies. I am also confused on that they mean by the numbers varying and how I put that into the equation.
 
I am confused on how I use the equation to find the cars average speed as the question specifies. I am also confused on that they mean by the numbers varying and how I put that into the equation.
What is the definition of speed that you have been taught?

Are you in Calculus yet?
 
By definition of speed do you mean like miles per hour or dist/time?
yes

average speed = (distance traveled) / (time elapsed)

Now referring back to the problem, let's do a(ii) first.

How would calculate the distance traveled, by the particle, from the given equation?
 
yes

average speed = (distance traveled) / (time elapsed)

Now referring back to the problem, let's do a(ii) first.

How would calculate the distance traveled, by the particle, from the given equation?
Would you plug the numbers into the equation, then get 2 answers for d and find the average?
 
Would you plug the numbers into the equation, then get 2 answers for d and find the average?
Yes and No. - Lets work step by step.

What is the value of "d" at t =2? [let's call that d(2)]

What is the value of "d" at t =4? [let's call that d(4)]

What does d(2) & d(4) represent - physically?
 
Yes and No. - Lets work step by step.

What is the value of "d" at t =2? [let's call that d(2)]

What is the value of "d" at t =4? [let's call that d(4)]

What does d(2) & d(4) represent - physically?
D when t=2 is 8,
And d when t=4 is 24

They represent the distance the car has gone after (t)?
 
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D when t=2 is 8,
And d when t=2 is 24

They represent the distance the car has gone after (t)?
Correct - but

They represent the distance - from where - the car has gone after (t)
 
I am unsure. Would it be the distance the car has gone at d(4) [so 8] - d(2) [24]?
Draw a little sketch.

Draw a line to indicate the "line of travel" of the car. Let us assume it is a st. line.

Draw a point O on the line to indicate cross-walk.

Now draw a point X2 to indicate position of car at t=2 (driving away from the cross-walk). The length OX2 will be the distance d(2) you have calculated (do you see that?).

Again draw a point X4 to indicate position of car at t=4 (driving away from the cross-walk). The length OX4 will be the distance d(4) you have calculated.

So the distance traveled in 2 to 4 minutes is [24-8=] 16 feet.

The elapsed time to travel [4 - 2 =] 2 minutes ............................................................................................edited

The car has traveled 16 feet in 2 minutes - what is its average speed? Please post your answer.

Do the same operations for part 'b (ii)'. Please post your detailed (showing steps) answer.

After that we will attack the part (i) of (a) and (b).
 
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Draw a little sketch.

Draw a line to indicate the "line of travel" of the car. Let us assume it is a st. line.

Draw a point O on the line to indicate cross-walk.

Now draw a point X2 to indicate position of car at t=2 (driving away from the cross-walk). The length OX2 will be the distance d(2) you have calculated (do you see that?).

Again draw a point X4 to indicate position of car at t=4 (driving away from the cross-walk). The length OX4 will be the distance d(4) you have calculated.

So the distance traveled in 2 to 4 minutes is [24-8=] 16 feet.

The elapsed time to travel [4 - 2 =] 2 minutes ............................................................................................edited

The car has traveled 16 feet in 2 minutes - what is its average speed? Please post your answer.

Do the same operations for part 'b (ii)'. Please post your detailed (showing steps) answer.

After that we will attack the part (i) of (a) and (b).
So since speed- distance/time, the average speed here would be d/t, thus 16/2, which is 8.

Then Isolved the other using the same steps:

d1=6.29
d2=10.56

Then,

d=4.27 and t=.7 so d/t= 6.1

And I understand the other parts of the question. Thank you for helping me through this problem.
 
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