To estimate th height of a building, a stone is dropped from the top of a building into a pool of water at groud level. How high is the building if the splash is seen 6.8 seconds after the stone is droppped?
I have to use the equation s(t) = -4.9t^2 + v(subscript 0)t + s(subscript 0)
Now the previous question of this series asked that I find the velocity of a projectile shot upward from the surface of the earth with an initial velocity of 120 meters per second, after 5 seconds, and after 10 seconds. My answers were 71 meters/sec and 22 m/sec respectively.
I did this by solving -9.8t + 120
Now, do I find v(6.8) = -9.8t + 120 ???
If so, that is 53.36.....but I highly doubt this is correct because that is the velocity afte 6.8 seconds, not the height of the building. I am stuck with what to do here.
Any help?
I have to use the equation s(t) = -4.9t^2 + v(subscript 0)t + s(subscript 0)
Now the previous question of this series asked that I find the velocity of a projectile shot upward from the surface of the earth with an initial velocity of 120 meters per second, after 5 seconds, and after 10 seconds. My answers were 71 meters/sec and 22 m/sec respectively.
I did this by solving -9.8t + 120
Now, do I find v(6.8) = -9.8t + 120 ???
If so, that is 53.36.....but I highly doubt this is correct because that is the velocity afte 6.8 seconds, not the height of the building. I am stuck with what to do here.
Any help?