word problem: Find three consecutive even integers such that

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Solve the following algebracially:Find three consecutive even integers such that the product of the smallest integer and the middle integer is eight less than eleven times the larger integer?
 
Solve (2n2)(2n)=11(2n+2)8\displaystyle (2n-2)(2n) = 11(2n+2)-8.
 
Ashley, do you understand why 2n-2 , 2n , 2n+2 represent 3 consecutive even integers?

If not, remember that n is ANY integer; ANY integer multiplied by 2 = even integer; capish?
 
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