will it burst?

[Guest]

A canister is dropped from a helicopter 500m above the ground. Its parachute does not open, but the canister has been designed to withstand an impact velocity of 100 m/s. will it burst?

I'm having trouble getting started with this one...i know i need to find some sort of gravity formula, and i'm trying to figure out if the impact velocity of the canister is >,<, or = to 100m/s. If someone could just help me get started i can take it from there.
Thanks

 

[royhaas]

Freefall is governed by \(\displaystyle s=(1/2)gt^2\), where \(\displaystyle s\) is the distance in meters, \(\displaystyle t\) is the time in seconds, and \(\displaystyle g=9.8 meters/sec^2\) is the acceleration of gravity.

 

[soroban]

Hello, 1backspace!

A canister is dropped from a helicopter 500m above the ground.
Its parachute does not open, but the canister has been designed to withstand an impact velocity of 100 m/s.
Will it burst?

The free-fall formula (in metrics) is: \(\displaystyle s(t)\;=\;s_o\,+\,v_ot\,-\,\frac{1}{2}gt^2\)
\(\displaystyle \;\;\) where \(\displaystyle s_o\) = initial position of the object, \(\displaystyle v_o\) = initial velocity, and \(\displaystyle g\,=\,9.8\,m/sec^2\)

This initial position is \(\displaystyle s_o\,=\,500\).
Since the canister is dropped, \(\displaystyle v_o\,=\,0\).

Hence, the position (height) function is: \(\displaystyle \,s(t)\;=\;500\,-\,4.9t^2\)

Can you finish it now?