dbngshuroy
New member
- Joined
- Aug 2, 2010
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I dont know where to post this question . So I am posting here.
Why the set of all natural numbers (N) has infinite number of elements. :?:
I have started from this....
Suppose N is finite and its largest element is x. Then x + 1 will be a natural number because addition of two natural num make another natural number which is greater than each previous numbers. clearly x+1>x which is contradicting x is largest. So N has no largest element. so N has infinite number of elements.
another way.......
we can build the set N = { x+1 | x is the element of N }
so if 1 is a natural number then 2 is also . as 2 is the element of N then 3 is also and so on 3,4,5,6,7,8,9,10,..........
So N is infinite.
Is these 2 proof is correct? If there there is any strong proof then kindly post them with some explanation.
Why the set of all natural numbers (N) has infinite number of elements. :?:
I have started from this....
Suppose N is finite and its largest element is x. Then x + 1 will be a natural number because addition of two natural num make another natural number which is greater than each previous numbers. clearly x+1>x which is contradicting x is largest. So N has no largest element. so N has infinite number of elements.
another way.......
we can build the set N = { x+1 | x is the element of N }
so if 1 is a natural number then 2 is also . as 2 is the element of N then 3 is also and so on 3,4,5,6,7,8,9,10,..........
So N is infinite.
Is these 2 proof is correct? If there there is any strong proof then kindly post them with some explanation.