Why is this 6?w

hypergolic

New member
Joined
Sep 30, 2015
Messages
1
t(6-1^t)= 6

So I got this from someone who has a mastergrade in mathemathics who wanted to see if I could explain why this is 6.
But I realy don`t know where to start so if someone could help me define this math piece I would be grateful.
 
t(6-1^t)= 6

So I got this from someone who has a mastergrade in mathemathics who wanted to see if I could explain why this is 6.

What is "this"? Is the above supposed to be some kind of limit? What is the meaning of your subject line, where you said that "this" is "6?w"?

Please be complete. Thank you! ;)
 
What you've posted there seems to me like a limit problem. The limit basically asks: what happens as (variable) gets closer and closer to (value)? In this case, we want to know what happens to the expression as t grows infinitely large. So, plug successively larger and larger values in for t. Do you notice a pattern? Do you see now why the limit is 6?

EDIT: The above post is completely invalid, as I misread the problem. Please ignore my failure :p
 
Last edited:
What you've posted there seems to me like a limit problem. The limit basically asks: what happens as (variable) gets closer and closer to (value)? In this case, we want to know what happens to the expression as t grows infinitely large.
I think we're all assuming the original question to have been the following:

. . . . .\(\displaystyle \displaystyle \mbox{Justify the following: }\, \lim_{t\, \rightarrow\, \infty}\, \left(6\, -\, 1^t\right)\)

So, plug successively larger and larger values in for t. Do you notice a pattern? Do you see now why the limit is 6?
What pattern, in 6 - 1 = 5, 6 - 1^2 = 5, 6 - 1^3 = 5, 6 - 1^4 = 5, ..., are you seeing that leads you to a limit value of 6? :oops:
 
t(6-1^t)= 6

So I got this from someone who has a mastergrade in mathemathics who wanted to see if I could explain why this is 6.
But I realy don`t know where to start so if someone could help me define this math piece I would be grateful.

As written, the above is incorrect, see stapel's post above. The only way I can see this making sense is if the limit part of the expression is
\(\displaystyle \underset{t\, \to\, \infty}{lim}\, 6\, (-1)^t\)
in which case one limit (accumulation point) is 6, i.e. 6 (-1)2t = 6, t \(\displaystyle \epsilon\, \mathbb{Z}\). Another is -6, i.e. 6 (-1)2t+1 = -6, t \(\displaystyle \epsilon\, \mathbb{Z}\). usw.
 
Stapel:

Thanks for the correction. I understand now. I completely misread the problem. I thought the expression was (6 - 1/t). I suppose I misread it precisely because that makes far more sense to me than what was actually written. I will edit my previous post as well to note that my proposed solution does not work.
 
Top