When two numbers are added together it equals 30....

[learnerjack]

When two numbers are added together it equals 30. Twice the second number is 6 more than 4 times the first number. What are these numbers? I want to solve algebraically.

 

[Deleted member 4993]

Re: Word Problem

When two numbers are added together it equals 30. Twice the second number is 6 more than 4 times the first number. What are these numbers? I want to solve algebraically.

Start with naming things.

What is being asked? - When two numbers ... What are these numbers?

Let the first number = F

Let the second number = S

"When two numbers are added together it equals 30"

Then

F + S = 30..........................(1)

S = 30 - F

Twice the second number is 6 more than 4 times the first number

2 * S = 6 + 4 * F.....................................(2)

Using (1)in (2)

2 * (30 - F) = 6 + 4 * F

Now solve for 'F' from above.

Then use (1) to solve for 'S'

Check your answer by using these values of 'F and 'S' into (1) & (2).

Please show your work, indicating exactly where you are stuck - so that we know where to begin to help you.

 

[winsome]

Solution:

Let us say first number is n. So the second number shall be (30-n)
Multiply the second number by 2, it yields = 2 (30 - n). This is ‘equal’ to 6 more than 4 times the first number (n). Say (4n + 6)

Thus we have 2(30-n) = 4n + 6

60 - 2n = 4n + 6
54 = 6n
n = 9
so first number is 9 and the other number is (30 - 9) = 21

We can check it now: 2(21) = 42 & 4(9) = 36, and one is 6 more than the other.
ads deleted

 

[mmm4444bot]

When two numbers are added together it equals 30. Twice the second number is 6 more than 4 times the first number. What are these numbers? I want to solve algebraically.

Start with naming things.

What is being asked? - When two numbers ... What are these numbers?

Let the first number = F

Let the second number = S

"When two numbers are added together it equals 30"

Then

F + S = 30..........................(1)

S = 30 - F

Twice the second number is 6 more than 4 times the first number

2 * S = 6 + 4 * F.....................................(2)

Using (1)in (2)

2 * (30 - F) = 6 + 4 * F

Now solve for 'F' from above.

Then use (1) to solve for 'S'

Check your answer by using these values of 'F and 'S' into (1) & (2).

Please show your work, indicating exactly where you are stuck - so that we know where to begin to help you.

Subhotosh, learnerjack is winsome, so there was no work to show until winsome returned to post it with advertising. In other words, winsome totally wasted your time.

 

[Denis]

win some, lose some ...