Hi,
Q: Position function of a particle is given by r(t) = <t^2,5t,t^2 - 16t>. When is the speed a minimum?
Thinking back to Calc 1 days, which I only vaguely remember, I thought I would need to take the second derivative and find at which values of t it equals zero to get the critical points... because the velocity should be at a minimum when speed is at a minimum since speed = |v|.
r'(t) = <2t,5,2t - 16>
This is my velocity function then.. derivative of that (acceleration):
r''(t) = <2,0,2>
Ok, this is my problem. r''(t) = 2i + 0j + 2k. But it's not a function of time anymore. So it can't ever = 0? I'm guessing I am messing up somewhere. Can you help?
Q: Position function of a particle is given by r(t) = <t^2,5t,t^2 - 16t>. When is the speed a minimum?
Thinking back to Calc 1 days, which I only vaguely remember, I thought I would need to take the second derivative and find at which values of t it equals zero to get the critical points... because the velocity should be at a minimum when speed is at a minimum since speed = |v|.
r'(t) = <2t,5,2t - 16>
This is my velocity function then.. derivative of that (acceleration):
r''(t) = <2,0,2>
Ok, this is my problem. r''(t) = 2i + 0j + 2k. But it's not a function of time anymore. So it can't ever = 0? I'm guessing I am messing up somewhere. Can you help?