what is (x with the exponent of 3/4) exponent -4
- Thread starter vikings4
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Until you're given a value for "x", I'm afraid there is no way to evaluate this expression (to find "what is" its value). Sorry!vikings4 said:
All you can do is apply exponent rules to simplify the expression.
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vikings4 said:
Your problem:
\(\displaystyle [x^{\frac{3}{4}}]^{-4}\)
To simplify, use one of the rules of exponents:
\(\displaystyle [x^a]^b \, = \, x^{(a\cdot b)}\)
vikings4 said:
You could simplify the expression. The problem is we don't know the role of the -4. Is the -4 an exponent of 3/4 or is it an exponent of the entire expression x[sup:26i5kse8]3/4[/sup:26i5kse8]?
I imagine it looks like this.
\(\displaystyle (x^{\frac{3}{4}})^{-4}\)
If so follow the rules of exponents.
a[sup:26i5kse8]x[/sup:26i5kse8]·a[sup:26i5kse8]y[/sup:26i5kse8]=a[sup:26i5kse8]x+y[/sup:26i5kse8]
(a[sup:26i5kse8]x[/sup:26i5kse8])[sup:26i5kse8]y[/sup:26i5kse8] = a[sup:26i5kse8]xy[/sup:26i5kse8]
a[sup:26i5kse8]-y[/sup:26i5kse8] = 1/a[sup:26i5kse8]y[/sup:26i5kse8]
etc.