Let a*b = the least common multiple of a and b. What is the sum of all natural number values of x such that 15*x = 45?
Huh. Weird.
The "Let" statement and the "What" question don't appear to have any connection, but there's at least one place online (
here, page 10, question 115) where one can see that, yes, indeed, they really are supposed to go together... somehow. (And, yes, the answer key, on page 16 of the same document, confirms that the answer is supposed to be "54".) :shock:
The actual Handbook (for 2001-2002) has the exercise
on page 20, but the solutions page (on page 21) just lists the answer; it does not explain how one is expected to use the given information to arrive at that answer. However...
Many times in these Handbooks (I've noticed, while trying to find the above information), exercises use "*" to mean "an operator that we will now define", rather than "times". So what I
think is going on is the following:
7. We will define the operation "@" as follows:
. . . . .a @ b = c
...where c is the Least Common Multiple of a and b. Under this definition, find the sum of all natural numbers x such that:
. . . . .15 @ x = 45
That is, find the sum of all natural numbers x such that the LCM of 15 and x is 45.
If this is a correct understanding (and, if so, shame on the authors for using such confusing notation!), then we have:
. . . . .45 = 3 * 3 * 5
. . . . .15 = 3 * 5
The only way 15 and x will have a LCM of 45 is if the following is true:
Code:
LCM:
15 : 3 * 5
x : ? * ? * ?
----+---------------
LCM : 3 * 3 * 5 = 45
(For an explanation of the method being used above, go
here.)
This means that x must have two copies of the factor 3 (so as to get the second copy for the LCM of 45), and maybe a copy of 5 (or not). So the only possible x-values would be 9 (which has that second copy of 3, but no copy of 5) and 45 (which has the second copy of 3, and also a copy of 5). These values sum to 54.
I'm not an advocate of giving out the answers, but this question was formatted so confusingly that I felt the need to make an exception. Comments and corrections are welcome!