what is the solution set to the next polynomial x4 + 2x3 + 3x2 = 0
Z zooba New member Joined Feb 18, 2015 Messages 7 Apr 26, 2015 #1 what is the solution set to the next polynomial x4 + 2x3 + 3x2 = 0 Last edited by a moderator: Apr 26, 2015
D Deleted member 4993 Guest Apr 26, 2015 #2 zooba said: x4 + 2x3 + 3x2 = 0 Click to expand... x4 + 2x3 + 3x2 = 0 x2 * (x2 + 2x + 3) = 0 Now continue....
zooba said: x4 + 2x3 + 3x2 = 0 Click to expand... x4 + 2x3 + 3x2 = 0 x2 * (x2 + 2x + 3) = 0 Now continue....
Z zooba New member Joined Feb 18, 2015 Messages 7 Apr 27, 2015 #3 i think the solution to the second part contains a complex number i think the solution to the second part contains a complex number which is: x = +i(2)1/2 - 1 And x = -i(2)1/2 - 1 is that correct.
i think the solution to the second part contains a complex number i think the solution to the second part contains a complex number which is: x = +i(2)1/2 - 1 And x = -i(2)1/2 - 1 is that correct.
D Deleted member 4993 Guest Apr 27, 2015 #4 zooba said: i think the solution to the second part contains a complex number which is: x = +i(2)1/2 - 1 And x = -i(2)1/2 - 1 is that correct. Click to expand... Looks good.. But you could have checked it yourself by multiplying it out: (x + 1 + i√2)(x + 1 - i√2) = (x+1)2 + (√2)2 = x2 + 2x + 1 + 2 = x2 + 2x + 3 ...... checks
zooba said: i think the solution to the second part contains a complex number which is: x = +i(2)1/2 - 1 And x = -i(2)1/2 - 1 is that correct. Click to expand... Looks good.. But you could have checked it yourself by multiplying it out: (x + 1 + i√2)(x + 1 - i√2) = (x+1)2 + (√2)2 = x2 + 2x + 1 + 2 = x2 + 2x + 3 ...... checks