We are choosing 3 out of 10 altogether. C(10,3)
We need 2 regular out of the 6, C(6,2)
And 1 of the 4 diet, C(4,1)
\(\displaystyle \frac{C(6,2)C(4,1)}{C(10,3)}\)
Note how the values in the numerator add up to the values in the denominator?.
6+4=10 and 2+1=3.