what is the probability that 2 cans of regular cola and 1 ca

Fiona09

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A cooler contains 10 cans of cola: 6 regular colas and 4 diet colas. If 3 cans of cola are selected at random, what is the probability that 2 cans of regular cola and 1 can of diet cola are selected?

Can someone help me solve this problem? :?
 
We are choosing 3 out of 10 altogether. C(10,3)

We need 2 regular out of the 6, C(6,2)

And 1 of the 4 diet, C(4,1)

\(\displaystyle \frac{C(6,2)C(4,1)}{C(10,3)}\)

Note how the values in the numerator add up to the values in the denominator?.

6+4=10 and 2+1=3.
 
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