what is the polynomial equal to when completly factored

[nae]

please help me understand this?

12mb-9m+8b-6

I know i group them (4mb-3m) +(4b-3)

would it be 4m(b-3)?

if not could someone please help me understand.

 

[galactus]

Hello nae:

The trick is to get what is inside the parentheses the same.

\(\displaystyle \L\\12mb-9m+8b-6\)

Factor:

\(\displaystyle \L\\3m(4b-3)+2(4b-3)\)

See there?. 4b-3 inside the parentheses. So, you have:

\(\displaystyle \L\\(3m+2)(4b-3)\)

 

[tkhunny]

please help me understand this?

12mb-9m+8b-6

I know i group them (4mb-3m) +(4b-3)

would it be 4m(b-3)?

How do you "know" you are to group them like that?

(4mb-3m) +(4b-3) = m*(4b-3) +(4b-3) = (m+1)(4b-3)

You can understand this better if you think about this

m*a + m = m*a + m*1 = m(a+1)

 

[stapel]

repost

I know i group them (4mb-3m) +(4b-3)

Yes; this was explained in your other thread on this exercise.

In the future, please post follow-ups and replies to the original threads. Thank you.

Eliz.