what is e?
- Thread starter cmklsk
- Start date
Hello, cmklsk!
I assume you didn't mean to have both \(\displaystyle R\) and \(\displaystyle r\) in the problem.
Also, "e" is an unfortunate choice for a variable . . . I'll use \(\displaystyle x.\)
We have: \(\displaystyle \:x^R \:=\:1\,+\,R\), where \(\displaystyle R\,=\,10\%\,=\,0.1\,=\,\frac{1}{10}\)
The equation is: \(\displaystyle \:x^{0.1} \:=\:1\,+\,0.1\)
. . Then we have: \(\displaystyle \:x^{\frac{1}{10}} \:=\:1.1\)
Raise both sides to the \(\displaystyle 10^{th}\) power: \(\displaystyle \:\left(x^{\frac{1}{10}}\right)^{10} \:=\
1.1)^{10}\)
Therefore: \(\displaystyle \:x\:=\1.1)^{10} \:=\:2.59374246...\)
I assume you didn't mean to have both \(\displaystyle R\) and \(\displaystyle r\) in the problem.
Also, "e" is an unfortunate choice for a variable . . . I'll use \(\displaystyle x.\)
We have: \(\displaystyle \:x^R \:=\:1\,+\,R\), where \(\displaystyle R\,=\,10\%\,=\,0.1\,=\,\frac{1}{10}\)
The equation is: \(\displaystyle \:x^{0.1} \:=\:1\,+\,0.1\)
. . Then we have: \(\displaystyle \:x^{\frac{1}{10}} \:=\:1.1\)
Raise both sides to the \(\displaystyle 10^{th}\) power: \(\displaystyle \:\left(x^{\frac{1}{10}}\right)^{10} \:=\
1.1)^{10}\)Therefore: \(\displaystyle \:x\:=\
1.1)^{10} \:=\:2.59374246...\)
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- Feb 4, 2004
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So "R" and "r" are different variables...? And you're asking for the value of a third variable, "e"...?cmklsk said:
With only one equation and three variables, it is not possible to arrive at an algebraic solution. Sorry.
Eliz.