what is e^lnx

[sozener1]

is exponential of lnx e^lnx = x???

 

[Deleted member 4993]

is exponential of lnx e^lnx = x???

Yes → e and ln are inverse of each other (like square[²] and square-roots [√] are)

by definition

ln(x) = a →

e^a = x →

e^ln(x) = x ..........edited

 

[HallsofIvy]

What definitions of \(\displaystyle e^x\) and \(\displaystyle ln(x)\) are you using?

 

[lookagain]

Yes → e and ln are inverse of each other (like square[2] and square-roots [√] are)

by definition

ln(x) = a →

e^a = x →

e^ln(x) = a \(\displaystyle \ \ \ \ \ \) These don't follow. See below.

You have ln(x) = a, and you have e^ln(x) = a, but e^ln(x) = x.


a can't equal both ln(x) and x.

 

[Deleted member 4993]

You have ln(x) = a, and you have e^ln(x) = a, but e^ln(x) = x.


a can't equal both ln(x) and x.

You are correct - the last line has a typo it should have been e^ln(x) = x

in other words:

ln(x) = a →

e^a = x →

e^ln(x) = x [FONT=MathJax_Main-Web][/FONT]

 

[Quaid]

a can't equal both ln(x) and x

That's right, for Intermediate Algebra; only when considering Complex logarithms can ln(a)=a.

It has something to do with a fella' named Lambert W.