GrannySmith
New member
- Joined
- Jan 4, 2014
- Messages
- 14
I am asking in regards to this function.
f(x) = √x + 3
I am supposed to find the x intercept, which you do by substituting 0 for f(x).
√x + 3 = 0
√x = 3
Could you not square both sides of the equation, and then get x = 9? Why doesn't this work algebraically?
f(x) = √x + 3
I am supposed to find the x intercept, which you do by substituting 0 for f(x).
√x + 3 = 0
√x = 3
Could you not square both sides of the equation, and then get x = 9? Why doesn't this work algebraically?