what do I do next

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jazzgirl

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Feb 15, 2010
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I have 3x-4/x^2-9 +2x-1/x+3
I factored out the x^2-9 so I have

3x-4/(X+3)(x-3) + 2x-1/x+3
 
jazzgirl said:
I have 3x-4/x^2-9 +2x-1/x+3
I factored out the x^2-9 so I have

3x-4/(X+3)(x-3) + 2x-1/x+3
Click to expand...

You don't tell us what has been asked of you?

Use parenthesis (and PEMDAS) to group your operations properly.
 
Sorry. I need to identify any x-values for which the expression is undefined

I tried to re-write it.

3x-4 + 2x-1
x^2-9 x+3
 
jazzgirl said:
Sorry. I need to identify any x-values for which the expression is undefined

I tried to re-write it.

3x-4 + 2x-1
x^2-9 x+3
Click to expand...

The expression goes "undefined" when any one of the denominators become equal to zero.

For what values of 'x', one of the denominators in the given expression become zero?
 
jazzgirl said:
-3 will make one of the denominators zero, right
Click to expand...

Yes, -3 is one of the values that you're looking for. What's the other?

Basically, you're solving the following two equations (each of which implies that a denominator will be zero).

x + 3 = 0

x^2 - 9 = 0

Also, when typing algebraic fractions, we need to put grouping symbols around numerators or denominators when they contain more than one term. Otherwise, it's confusing.

(3x - 4)/(x^2 - 9) + (2x-1)/(x+3)
 
Ok to solve x^2- 9 do I factor it out?

(x-3)(x+3) so besides -3 being te answer 3 will also be the answer.
right?
 
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