Find the volume of a triangular pyramid whose base is equilateral with each side 6 meters long. The vertex of the pyramid is 3 meters directly over the incenter of the triangle.
Now if the triangle is equilateral then the height must be 3 SqRt 3, therefore the area of the base is 18 SqRt 3 divided by 2 = 9 SqRt 3
Then I am assuming since the incenter of a traingle is the exact center of a triangle and the vertex is directly over it, then the 3 meters must be the height of the pyramid.
So i multiplied the 9 SqRt 3 by 3 = 27 SqRt 3
That is what i got as my volume. Is this correct?
Now if the triangle is equilateral then the height must be 3 SqRt 3, therefore the area of the base is 18 SqRt 3 divided by 2 = 9 SqRt 3
Then I am assuming since the incenter of a traingle is the exact center of a triangle and the vertex is directly over it, then the 3 meters must be the height of the pyramid.
So i multiplied the 9 SqRt 3 by 3 = 27 SqRt 3
That is what i got as my volume. Is this correct?
