phillygurl
New member
- Joined
- Feb 13, 2010
- Messages
- 12
I have tried this and it doesn't seem right?
The volume of rubber in the hollow ball used in racquetball is modeled by the formula,
V = 4/3 iiR^3 - 4/3 iir^3
a) rewrite the formula by factoring the right hand side completely
V = 4/3 iiR^3 - 4/3iir^3
= 4/3 ii - 4/3 ii
= R^3 - r^3
V = R^3 - r^3
b) determine the value of V when R = 3cm and r = 1.5cm
V = 4/3ii(3)^3 - 4/3ii(1.5)^3
= 4/3ii(3 x 3 x 3 = 27) - 4/3ii(1.5 x 1.5 x 1.5 = 3.375)
= 4/3ii x 27/1 = 36 - 4/3ii x 3.375/1 = 4.5
= 36 - 4.5
= 31.5
V = 31.5cm
The volume of rubber in the hollow ball used in racquetball is modeled by the formula,
V = 4/3 iiR^3 - 4/3 iir^3
a) rewrite the formula by factoring the right hand side completely
V = 4/3 iiR^3 - 4/3iir^3
= 4/3 ii - 4/3 ii
= R^3 - r^3
V = R^3 - r^3
b) determine the value of V when R = 3cm and r = 1.5cm
V = 4/3ii(3)^3 - 4/3ii(1.5)^3
= 4/3ii(3 x 3 x 3 = 27) - 4/3ii(1.5 x 1.5 x 1.5 = 3.375)
= 4/3ii x 27/1 = 36 - 4/3ii x 3.375/1 = 4.5
= 36 - 4.5
= 31.5
V = 31.5cm