very simple: log_{2+sqrt[3]}(2 - sqrt[3])

[7Hero]

\(\displaystyle \Large{ \log_{2+\sqrt{ 3\,}}\left(2\, -\, \sqrt{ 3\,}\right)^2 }\)

help with steps pls

 

[mmm4444bot]

What have you thought about or tried so far? Please read the forum guidelines. :cool:

Here is a hint:

\(\displaystyle \dfrac{1}{2 + \sqrt{3}} = 2 - \sqrt{3}\)

 

[Deleted member 4993]

What have you thought about or tried so far? Please read the forum guidelines. :cool:

Here is a hint:

\(\displaystyle \dfrac{1}{2 + \sqrt{3}} = 2 - \sqrt{3}\)

Nice hint Mark --- made me think

 

[7Hero]

I made it thank you : ))