colormekaylee
New member
- Joined
- Aug 1, 2009
- Messages
- 12
The Orginial Problem is :
(3x+3y+3 )/(9x ) ÷ (x^2+ 2xy+y^(2 )-1)/(x^4- x^2 ) ( It looked alot better on word)
I know that to start, you need to flip the second problem so it would look like this :
(3x+3y+3 )/(9x ) x (x^4- x^2 )/ (x^2+ 2xy+y^(2 )-1)
I have had trouble getting any further, I put the problems together, but when it gets to the point of factoring them i am completley lost, so basically im here:
(3x+3y+3)(x^4- x^2 )
(9x)(x^2+ 2xy+ y^(2) - 1)
Where do I go from here?
(3x+3y+3 )/(9x ) ÷ (x^2+ 2xy+y^(2 )-1)/(x^4- x^2 ) ( It looked alot better on word)
I know that to start, you need to flip the second problem so it would look like this :
(3x+3y+3 )/(9x ) x (x^4- x^2 )/ (x^2+ 2xy+y^(2 )-1)
I have had trouble getting any further, I put the problems together, but when it gets to the point of factoring them i am completley lost, so basically im here:
(3x+3y+3)(x^4- x^2 )
(9x)(x^2+ 2xy+ y^(2) - 1)
Where do I go from here?