Vertex of Parabola

[rose]

how do i find the vertex of a parabola using the format ax2+bx+c?

 

[stapel]

how do i find the vertex of a parabola using the format ax2+bx+c?

They were supposed to have covered this in class. Since we can't teach classes here, please try some online lessons, such as at this link.

I'm assuming that you accidentally omitted the "y=" which is the rest of the equation for the parabola. There are various methods you can apply to y = ax^2 + bx + c; use whichever one you prefer.

 

[Quaid]

For a quadratic equation in the form y = ax^2 + bx + c, there are different methods to determine the parabola's vertex coordinates; if you're in a math class, I don't know what they're working on.

One method is to use a formula, in terms of the given coefficients a and b, to first calculate the x-coordinate of the vertex point. After you determine the x-coordinate, use it in the given equation, to calculate the associated y-coordinate.

The x-coordinate of the vertex is x = -b/(2a)


Here's an example of this method.

Given y = 4x^2 + 7x - 13, we see that a = 4 and b = 7

x = -b/(2a)

x = -7/(2*4)

x = -7/8

The x-coordinate of the vertex point is -7/8. Now we calculate the y-coordinate.

y = 4x^2 + 7x - 13

y = 4(-7/8)^2 + 7(-7/8) - 13

y = -257/16

The vertex point of the given parabola has coordinates (-7/8, -257/16)

Please show your work, if you would like more help.

 

[rose]

Thank you soooo much I get it now