vertex for f(x) = 2x^2 - 6x + 1

haliebre

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Apr 4, 2006
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Give the vertex for f(x) = 2x^2 -6x +1

I can get the first part (3/2, ) but then I am stuck?
 
the y-value is f(3/2) ... substitute 3/2 in for x and do the arithmetic.
 
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