verifying trig identities: cos^2 * csc *sec=cot, etc.
- Thread starter brettg
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Re: verifying trig identities
Please share with us your work/thoughts - so that we know where to begin to help you.
Also use parentheses to group your operations correctly. For example, The 4 the problem - is it:
sec^2(x) - 1/sin^2(x) = sec^2(x)
or
[sec^2(x) - 1] / sin^2(x) = sec^2(x)
or something else.....
brettg said:
Please share with us your work/thoughts - so that we know where to begin to help you.
Also use parentheses to group your operations correctly. For example, The 4 the problem - is it:
sec^2(x) - 1/sin^2(x) = sec^2(x)
or
[sec^2(x) - 1] / sin^2(x) = sec^2(x)
or something else.....
Re: verifying trig identities
One approach is to convert all the functions into terms of sine and cosine.
cos^2 * csc *sec=cot (Of course this is meaningless. I'll go ahead and give it some meaning.)
cos^2(x) * csc x *sec x=cot x
\(\displaystyle \frac{\cos^2x}{1}\cdot \frac{1}{\sin x}\cdot \frac{1}{\cos x}\) = ???
Certainly, you can simplify this and end up with the desired result.
One approach is to convert all the functions into terms of sine and cosine.
cos^2 * csc *sec=cot (Of course this is meaningless. I'll go ahead and give it some meaning.)
cos^2(x) * csc x *sec x=cot x
\(\displaystyle \frac{\cos^2x}{1}\cdot \frac{1}{\sin x}\cdot \frac{1}{\cos x}\) = ???
Certainly, you can simplify this and end up with the desired result.
Re: verifying trig identities
If you are saying that you cannot simplify a multiplication of fractions by dividing out factors that are common to a numerator and denominator, then I'm afraid you need more help than we can give you here. Loren changed your problem to one that is equivalent in form to this arithmetic problem that you should have learned how to do in grade school:
(5[sup:3l0o3svh]2[/sup:3l0o3svh] / 1 )* (1/4)*(1/5)
And, if we DO the problem for you, then that's not likely to prepare you for this test. You need to talk to your classroom teacher about getting some extra help.
brettg said:
If you are saying that you cannot simplify a multiplication of fractions by dividing out factors that are common to a numerator and denominator, then I'm afraid you need more help than we can give you here. Loren changed your problem to one that is equivalent in form to this arithmetic problem that you should have learned how to do in grade school:
(5[sup:3l0o3svh]2[/sup:3l0o3svh] / 1 )* (1/4)*(1/5)
And, if we DO the problem for you, then that's not likely to prepare you for this test. You need to talk to your classroom teacher about getting some extra help.
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I would suspect that just about all of the tutors, and a good proportion of the users, know how to prove trig identities. However, as pointed out earlier, our giving you the worked solution to copy into your homework isn't going to help you learn, or help you pass the quizzes and tests.brettg said:
If you would like to learn, please reply showing what you have tried, starting with the actual problem statements (which included arguments for the various trig functions). If you are unable to make any start at all, then the previous advice holds: You have been badly mis-placed, and need immediately to hold a serious conference with your instructor or academic advisor about enrolment in a course for which you're ready.
Eliz.