Verifying answer (number of bacteria in culture at x=0, x=5)

charlesjoy

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Good morning. Can you verify my work for me?

The problem is as follows: The number of backteria growing in an incubation culture increases with time according to B(x)=4300(3)^x, where x is time in days. Find the number of bacteria when x=0 and x=5.

B(0)=4300(3)^0 which comes out to be just 4300.

B(5)=4300(3)^5 comes out to be 1,044,900.

Answers are 4300 and 1,044,900.
 
Re: Verifying answer

charlesjoy said:
Good morning. Can you verify my work for me?

The problem is as follows: The number of backteria growing in an incubation culture increases with time according to B(x)=4300(3)^x, where x is time in days. Find the number of bacteria when x=0 and x=5.

B(0)=4300(3)^0 which comes out to be just 4300.

B(5)=4300(3)^5 comes out to be 1,044,900.

Answers are 4300 and 1,044,900 <<< Correct - as far as I can see.
 
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