charlesjoy
New member
- Joined
- Mar 26, 2009
- Messages
- 38
Good morning. Can you verify my work for me?
The problem is as follows: The number of backteria growing in an incubation culture increases with time according to B(x)=4300(3)^x, where x is time in days. Find the number of bacteria when x=0 and x=5.
B(0)=4300(3)^0 which comes out to be just 4300.
B(5)=4300(3)^5 comes out to be 1,044,900.
Answers are 4300 and 1,044,900.
The problem is as follows: The number of backteria growing in an incubation culture increases with time according to B(x)=4300(3)^x, where x is time in days. Find the number of bacteria when x=0 and x=5.
B(0)=4300(3)^0 which comes out to be just 4300.
B(5)=4300(3)^5 comes out to be 1,044,900.
Answers are 4300 and 1,044,900.