soccerball3211
Junior Member
- Joined
- May 16, 2005
- Messages
- 84
(a) If a particle's position is given by x = (14) + (-15) t + (16) t2 (where t is in seconds and x is in meters), what is its velocity at t = 1 s? (b) What is its speed just then?
First I differentiate the displacement to get the velocity equation.
velocity=32t-15, then I plug in t=1 and get +17m/s
and then for part B i got 17 m/s?
Did I perform the right calculations?
First I differentiate the displacement to get the velocity equation.
velocity=32t-15, then I plug in t=1 and get +17m/s
and then for part B i got 17 m/s?
Did I perform the right calculations?