Velocity help

asissa

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Sep 6, 2009
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The book explains the standard vertical motion model (h=-16tsquared + vt + s), but this word problem has thrown me. Help!

A diver jumps from a diving board that is 24 feet above the water. The height of the diver is given by h=-16(t-1.5)(t+1) where the height h is measured in feet, and the time t is measured in seconds. When will the diver hit the water?

This is probably really simple and I'm reading more into this. Thanks.
 
asissa said:
The book explains the standard vertical motion model (h=-16tsquared + vt + s), but this word problem has thrown me. Help!

A diver jumps from a diving board that is 24 feet above the water. The height of the diver is given by h=-16(t-1.5)(t+1) where the height h is measured in feet, and the time t is measured in seconds. When will the diver hit the water?

This is probably really simple and I'm reading more into this. Thanks.

In other words - for what value of 't' - you'll get h = 0

You should be able to answer that "by observation".

For left hand side to be zero, one of the factors of right-hand-side must be equal to zero.[/spoiler:2qtzukey]
 
This won't answer the question, but if you multiply h = -16(t - 1.5)(t + 1) out, you get -16(t^2 - 0.5t - 1.5) = -16t^2 + 8t + 24, which is in the form given for projectile motion. v = 8 and s = 14.
 
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