Vector spaces

Filip84

New member
Joined
Oct 21, 2013
Messages
9
Hi,

can somebody check if this is correct:

Prove that in an n-dimensional vector space any set of n+1 vectors is linearly dependent.

Solution:

Vn is vector space over field F.
Dimension of Vn is n, which imply that basis B of Vn is B={b1, b2, ..., bn}. b1, b2, ..., bn are elements of Vn , and they are linearly independent (by definition of Basis).


Hence we can write:

c1b1+c2b2+...cnbn=bn+1 ,where ci is an element of F.
Conclusion: Set {b1, b2, ..., bn, bn+1} is linearly dependent.

Thanks.
 
You are to prove any set of vectors is a linearly dependent set. You assumed something about your set of vectors, that a subset of them is a basis. With a little bit of tweaking you can make your proof work.
 
Could you give me a hint?:)

I'll do it for 1 dimension to show you. Suppose B={b} is a basis for V, and consider a set of 2 (nonzero) vectors {v,w}.

Then v and w can be written as a linear combination of elements of B, i.e. v=s*b, w=t*b.

Consider the equation \(\displaystyle c_1v+c_2w=0\). Substituting we have \(\displaystyle c_1s\cdot b + c_2t\cdot b = (c_1s+c_2t)b=0\), i.e. \(\displaystyle c_1 = -c_2t/s\) gives a nontrivial solution to the equation (pick any value of c_2 you want), so {v,w} is linearly dependent.
 
Top