Vector Equation Line: An object was fired from position vector q = (10, -10,20)...

helloWorld600

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Jan 4, 2017
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I have this question,

An object was fired from position vector q = (10, -10,20) in the direction given by v = (20,-30,10), calculate coordinates of the point after time t = 3.

this is what I did:

r=q+vt
r=(10,-10,20)+3(20,-30,10)
r=(10,-10,20)+(60,-90,30)
r=(70,-100,50)


is this correct?
 
I have this question,

An object was fired from position vector q = (10, -10,20) in the direction given by v = (20,-30,10), calculate coordinates of the point after time t = 3.

this is what I did:

r=q+vt
r=(10,-10,20)+3(20,-30,10)
r=(10,-10,20)+(60,-90,30)
r=(70,-100,50)


is this correct?
Is this object travelling with constant velocity (i.e. a(cceleration) = 0)?
 
Generally speaking, most math problems at this level greater simplify things and ignore a lot of real world factors such as gravity, wind resistance, etc. If what you quoted in your initial post was exactly, quoted word-for-word, what the problem text said, then I think it's safe to assume you're meant to work with a constant velocity. If that's the case, that would make your answer correct. If you wish, you could ask your teacher for clarification.
 
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