Hey guys,
I have couple of issues with the following 6 problems:
1).
lim x^3 (sin^2) ( 1/x) =?
x > 0
the > is the sign for an arrow pointing to zero. I don't know how to solve for sin version of limits. I got the answer of 0 but it doesnt seem right (just simple plug in?)
2.) Suppose you know that h is an odd function,
and that lim h(x) = -5. Then lim h(x) = ?
x > 3^+ x > -3^-
3.) for y = (x-2)/(x-3) i wanted to know is this removable or non-removable
i thought it would be non-removable discontinuity but my friend says im wrong
4.) g(x) = 2/3x, [x, x + h],
this is dealing with derivatives
i got 2 / 3 (x + h) x for my answer
5.) Find d / dx at the point (0, p/2) on the curve implicitly defined by
cos [Pi(x^3)-y] = xy
I got Pi (3.14) as my final answer
6.) Find dy/dx at the point (1, 1) on the curve implicitly defined by
(x^3)(y) -3(x^2) + 4(y^3) = 2
Any help or tips would be greatly appreciated. Thanks in advance
I have couple of issues with the following 6 problems:
1).
lim x^3 (sin^2) ( 1/x) =?
x > 0
the > is the sign for an arrow pointing to zero. I don't know how to solve for sin version of limits. I got the answer of 0 but it doesnt seem right (just simple plug in?)
2.) Suppose you know that h is an odd function,
and that lim h(x) = -5. Then lim h(x) = ?
x > 3^+ x > -3^-
3.) for y = (x-2)/(x-3) i wanted to know is this removable or non-removable
i thought it would be non-removable discontinuity but my friend says im wrong
4.) g(x) = 2/3x, [x, x + h],
this is dealing with derivatives
i got 2 / 3 (x + h) x for my answer
5.) Find d / dx at the point (0, p/2) on the curve implicitly defined by
cos [Pi(x^3)-y] = xy
I got Pi (3.14) as my final answer
6.) Find dy/dx at the point (1, 1) on the curve implicitly defined by
(x^3)(y) -3(x^2) + 4(y^3) = 2
Any help or tips would be greatly appreciated. Thanks in advance