Variables on both sides-help!

Joined
Oct 6, 2005
Messages
5
I've done these problems a million times, and I'm still not getting them. Here's my current problem:

3/2y-y=4+ 1/2y

I've gotten to this point:

1/2y=4+1/2y

I'm stuck! I don't remember how to figure out the rest. I'm homeschooled, and my dad takes care of algebra. He's tried time and time again, and I still don't understand how to solve this problem. I've read, re-read, and re-re-read. Can anyone clue me in as to what to do next? Thanks!

Edit: I thought that I could combine my 1/2y together, so I tried that-and I got that I have to subtract 1/2y from each side, which leaves me with y=4. However, dad says this isn't the answer. SO, to add to my plea above, what did I do wrong?
 
You are probably doing it right, ending up with
0=4
There is no solution.
 
Thank you!!! I was sure it was something along those lines, but dad was adamant that I was wrong...:roll: silly engineers. Thanks again! :)
 
Top