the question reads... For certain values of the constant m the function f defined by f(x) = e^mx is a solution of the differential equation
(d^3y/dx^3)-3(d^2y/dx^2)-4(dy/dx)+12y=0
i got the 2nd and 3rd derivative.. then plugged in but i got to the point in which i got this
e^mx(m^3-3m^2-4m+12)
so then e^mx=0... but i dont know how to solve for (m^3-3m^2-4m+12) .. Please explain the process
Thank u!
(d^3y/dx^3)-3(d^2y/dx^2)-4(dy/dx)+12y=0
i got the 2nd and 3rd derivative.. then plugged in but i got to the point in which i got this
e^mx(m^3-3m^2-4m+12)
so then e^mx=0... but i dont know how to solve for (m^3-3m^2-4m+12) .. Please explain the process