Value of integration

You're talking not about "the value of integration", but about the value of the definite integral!

It looks like you did the work correctly (to get 68), but failed to copy it correctly. The integral of 5 is 5t, not 5 as you wrote.
 
Dr.Peterson said:
You're talking not about "the value of integration", but about the value of the definite integral!

It looks like you did the work correctly (to get 68), but failed to copy it correctly. The integral of 5 is 5t, not 5 as you wrote.
Click to expand...
Where do I need to include 5t?
 
I presume you just have to compare what you typed to what you had on paper, because the original work must have been correct, as you got the right answer.

If you have no work on paper, then go through what you typed, line by line, and check it. That is something you need to learn to do anyway (think, tests!), so this is a good chance to practice it. I've told you more than you need to know in order to find it.
 
Dr.Peterson said:
I presume you just have to compare what you typed to what you had on paper, because the original work must have been correct, as you got the right answer.

If you have no work on paper, then go through what you typed, line by line, and check it. That is something you need to learn to do anyway (think, tests!), so this is a good chance to practice it. I've told you more than you need to know in order to find it.
Click to expand...
Would it be the part that I labeled “integrating into the equation”?
 
I told you where the error was, didn't I? This shouldn't be hard.

I said, "The integral of 5 is 5t, not 5 as you wrote." Where did you integrate something? (That is, where did you find an antiderivative?) Look at what you wrote, and find a 5. Is that what you meant to write?

By the way, "integrating into the equation" doesn't mean anything. In fact, there is no equation here at all.
 
Dr.Peterson said:
I told you where the error was, didn't I? This shouldn't be hard.

I said, "The integral of 5 is 5t, not 5 as you wrote." Where did you integrate something? (That is, where did you find an antiderivative?) Look at what you wrote, and find a 5. Is that what you meant to write?

By the way, "integrating into the equation" doesn't mean anything. In fact, there is no equation here at all.
Click to expand...
How is this?

77CB2279-338A-4ECE-AFC9-A8AF20662994.jpeg
 
No, the given function which you want to integrate (called the integrand) is NOT -3t2 + 16t + 5t. And if it were, then why not add the 16t and 5t to get 21t?? Also the integral of 5t is NOT 5t, rather it is 5t^2/2.

To make life easier for everyone I will point out that Dr Peterson suggested that you did NOT integrate 5 correctly. So do not change what you initially were integrating but rather integrate correctly.

Please try again and post back.
 
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