using washer method to calculate area between curves

[xhappysnowmanx]

y=e^(x/2) y=e^(-x) on the interval ln2 less than or equal to x less than or equal to ln3.

i drew a rough graph showing that e^(x/2) has higher values than e^(-x)

so i have the integral of e^(x/2)-e^(-x) to be evaluated for ln3 - ln2.

i know how to complete the integral (or integrand, not good at terminology) but im stuck at getting the right integral for e^(x/2) and e^(-x). i.e. right now the e's are on the right hand side of the curvy line that mean integral. what would they look like on the left side and could it be explained step by step

 

[tkhunny]

You seem a bit confused. "Washer" would be for a volume, not an area. What is ti you are trying to do?

That curly line thing is a stylized 's'.

 

[xhappysnowmanx]

i meant volume

 

[tkhunny]

I just love it when a question is answered so curtly. It's your opportunity to show that you've learned something. In particular, it would be an opportunity for you to include the ENTIRE problem statement. When rotating a figure about a line, one likely would need to know what line we're using. Care to share?

Please be thorough and complete.