Using trig ratios to solve for missing values

[andyleija]

I understand how to solve for trig ratios when all the values are present but I don't know how to solve for missing ratios. Thanks!

The directions say to use trig ratios to solve for x and y in each right triangle.

1.

Angle a = 20 degrees
Angle b = 70 degrees
Angle c = 90 degrees
Side A = y units
Side B = x units
Side C = 12 units

2.

Angle a = y degrees
Angle b = x degrees
Angle c = 90 degrees
Side A = 18 units
Side B = 28 units
Side C = sqrt 1108

I know it's already summer, but help is appreciated!

 

[Aladdin]

\(\displaystyle For the first graph\)

\(\displaystyle Use\) \(\displaystyle sin(20)=opp/hyp=y/12 > y=sin(20)*(12)\)

\(\displaystyle Using\) \(\displaystyle cos(20)=adj/hyp=x/12 > x=cos(20)*(12\)


\(\displaystyle For the second graph\)

\(\displaystyle tan(y)=opp/adj= .... Continue\)

[sub:1poho5ht]Aladdin[/sub:1poho5ht]