Using the Quadratic Formula???

[confused20]

I am having difficulty with the following problem because I do not know how to use the quadratic formula. Can anyone explain step by step on how to do the following problem using the quadratic formula?

x^2/(2.00-x)(1.00-x) = .64

Any input will be greatly appreciated. Thank you.

 

[Loren]

>x^2/(2.00-x)(1.00-x) = .64 means \(\displaystyle \frac{x^2}{2-x}(1-x)=.64\). Is that what you mean?
At any rate, in order to use the quadratic formula, you must manipulate the equation into the form
\(\displaystyle ax^2+bx+c=0\) where a, b and c are constants. Then you simply plug those values into the quadratic formula and simplify the result. I guess you have the quadratic formula as
\(\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\).

I rather imagine that you meant x^2/((2.00-x)(1.00-x)) = .64 which means \(\displaystyle \frac{x^2}{(2-x)(1-x)}=.64\) in which case, after simplification you should get \(\displaystyle 9x^2+48x-32=0\). From this, a=9, b=48 and c=-32. Plug those values into the formula and simplify.