Using the Quadratic Formula Part 2

confused20

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Mar 9, 2008
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I was having difficulty solving a quadratic equation in which one has two different values for x as the numerator. Here is the problem:

(0.100 + X)(X)/(0.100 - X) = 1.8 x 10^-5

Any input on the above question will be greatly appreciated. Thank you to the individual who answered my last question.
 
confused20 said:
I was having difficulty solving a quadratic equation in which one has two different values for x as the numerator. Here is the problem:

(0.100 + X)(X)/(0.100 - X) = 1.8 x 10^-5

Any input on the above question will be greatly appreciated. Thank you to the individual who answered my last question.

\(\displaystyle \frac{0.1 \,+\, x}{0.1\,-\, x} = 1.8 \cdot 10^{-5}\)

Multiply both sides by (0.1 - x) - then continue...
 
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