Using Log to Undo an Exponent - Ex 3

[Jason76]

a.)

\(\displaystyle y = 2^{x}\)

\(\displaystyle \log_2(y) = \log_{2}(2^{x})\)

\(\displaystyle \log_{2}(y) = x\) - What is the next step?

This next example is very clear:

b.)

\(\displaystyle 8 = 2^{x}\)

\(\displaystyle \log_{2}(8) = \log_{2}(2^{x})\)

\(\displaystyle 3 = x\)

 

[Jason76]

Oh, wait I caught my error. Two unknown variables, so no solution.

 

[Deleted member 4993]

a.)

\(\displaystyle y = 2^{x}\)

\(\displaystyle \log_2(y) = \log_2(2^{x})\)

\(\displaystyle \log_2(y) = x\) - What is the next step?

This next example is very clear:

b.)

\(\displaystyle 8 = 2^{x}\)

\(\displaystyle \log_2(8) = \log_2(2^{x})\)

\(\displaystyle 3 = x\)

What were you asked to do? You need to supply complete question/s!

Oh, wait I caught my error. Two unknown variables, so no solution.

There is a solution! Depending on what was being asked (which you failed to mention).

If the first problem asked you to solve for 'x' - then the solution would be:

\(\displaystyle \displaystyle x = \frac{ln(y)}{ln(2)}\) or equivalent