(-2x^-2)^2 is the answer 2/x^4?
D Deleted member 4993 Guest Sep 25, 2007 #2 Generally You are given an equation - to solve for something. In this case you don't have an equation (no 'equal to' sign). May be you were asked to 'simplify'? Did you post the complete problem?
Generally You are given an equation - to solve for something. In this case you don't have an equation (no 'equal to' sign). May be you were asked to 'simplify'? Did you post the complete problem?
E evan399 New member Joined Sep 24, 2007 Messages 39 Sep 25, 2007 #3 yes, I am supposed to simplify it.
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Sep 25, 2007 #4 Re: use rules of exponents to slove Hello, evan399! \(\displaystyle \left(-2x^{-2}\right)^2\) is the answer: \(\displaystyle \L\:\frac{2}{x^4}\;\) . . . no Click to expand... We have: \(\displaystyle \:\left(-2x^{-2}\right)^2 \;=\;(-2)^2\left(x^^{-2}\right)^2 \;=\;4x^{-4} \;=\;\L\frac{4}{x^4}\)
Re: use rules of exponents to slove Hello, evan399! \(\displaystyle \left(-2x^{-2}\right)^2\) is the answer: \(\displaystyle \L\:\frac{2}{x^4}\;\) . . . no Click to expand... We have: \(\displaystyle \:\left(-2x^{-2}\right)^2 \;=\;(-2)^2\left(x^^{-2}\right)^2 \;=\;4x^{-4} \;=\;\L\frac{4}{x^4}\)