Use integration by parts to evaluate integral: int[0,3] ln(x^2+9) dx

blue27

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Use integration by parts to evaluate this integral:

. . . . .\(\displaystyle \displaystyle \int_0^3\, \ln(x^2\, +\, 9)\, dx\)
 

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Use integration by parts to evaluate this integral:

. . . . .\(\displaystyle \displaystyle \int_0^3\, \ln(x^2\, +\, 9)\, dx\)
Okay, what have you tried? Perhaps the basic formulation?

Here's the Indefinite Version

\(\displaystyle \int\ln\left(x^{2}+9\right)\;dx = x\cdot\ln\left(x^{2}+9\right)-\int\;x\;d\left[\ln\left(x^{2}+9\right)\right]\)

Where do we go from there?
 
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