To give us a start is this
1−6 cos2(B)sin2(B)−5 cos2(B)
Here's a hint: 1=sin2(B)+cos2(B). Use this in the denominator.
-Dan
MEBC01 said:sin^2(B)-5cos^2(B)/1-6cos^2(B)
Look more carefully:Okay, I believe the answer is
sin^2(B)-5cos^2(B)/6sin^2(B)