Urgent Surds Help please: 2y sqrt2 - 3 = 5y / sqrt2 + 1

[karliem]

I just cannot get this answer right:

2y sqrt2 - 3 = 5y / sqrt2 + 1

I have tried so many different methods, someone please help, this homework is due tomorrow

 

[stapel]

2y sqrt2 - 3 = 5y / sqrt2 + 1

Does the above mean any of the following?

. . . . .\(\displaystyle \L 2y\sqrt{2}\, -\, 3\, =\, \frac{5y}{\sqrt{2}}\, +\, 1\)

. . . . .\(\displaystyle \L 2y\sqrt{2\, -\, 3}\, =\, \frac{5y}{\sqrt{2}}\, +\, 1\)

. . . . .\(\displaystyle \L 2y\sqrt{2}\, -\, 3\, =\, \frac{5y}{\sqrt{2}\, +\, 1}\)

Or does it mean something else?

I have tried so many different methods...

Please reply showing that work. Thank you.

Eliz.

 

[karliem]

. . . . .\(\displaystyle \L 2y\sqrt{2}\, -\, 3\, =\, \frac{5y}{\sqrt{2}}\, +\, 1\)

its the one above

thanks so much

 

[stapel]

What have you tried? Where are you stuck? You added "3" to both sides, and subtracted "5y/sqrt[2]" from both sides. Maybe you multiplied through then by sqrt[2], to get rid of the one denominator. Then what?

Thank you.

Eliz.

 

[Denis]

hint: 2y sqrt(2) times sqrt(2) = 4y ; capish?