collegekid
New member
- Joined
- Nov 14, 2010
- Messages
- 8
Find the units digit of the sum 8^48 + 4^96 + 7^411
I started out by finding the pattern.
8^48
8^1=8
8^2=64
8^3=512
8^4=4096
N^4=6
4^96
4^1=4
4^2=16
N^4=6
7^411
7^1=7
7^2=49
7^3=343
7^4=2401
=3
My Answer:The sums of the units digits equals 6+6+3=15
(I stated this as my answer, but my professor stated "yes, but this doesn't answer the question")
Can anyone help me figure out what she's asking? i thought she was asking for the sum of the units digits..
I started out by finding the pattern.
8^48
8^1=8
8^2=64
8^3=512
8^4=4096
N^4=6
4^96
4^1=4
4^2=16
N^4=6
7^411
7^1=7
7^2=49
7^3=343
7^4=2401
=3
My Answer:The sums of the units digits equals 6+6+3=15
(I stated this as my answer, but my professor stated "yes, but this doesn't answer the question")
Can anyone help me figure out what she's asking? i thought she was asking for the sum of the units digits..