Unit circle

carebear

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Aug 30, 2010
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I don't understand the following question....where should I start?

If P(theta) is a point on the unit circle, then P(24) lies in which quadrant? I am confused as I thought P should be a coordinate (x,y)....so I do not understand the 24.

Please help
 
It's a Unit Circle. Every trip around causes a trip of length \(\displaystyle 2\pi\)

A trip of length 24 would be \(\displaystyle \frac{24}{2\pi}\;=\;3.8197\) trips around the Unit Circle.

3 full trips brings you back to where you started. Where does the last 0.8197 leave you?
 
P(theta)=(a cos(theta) , a sin(theta) )

since it is unit circle a=1

P(theta)=(cos(theta) , sin(theta) )

theta usually they given degree

so, P(24)=(cos(24), sin(24)).
 
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