Undetermined Coefficients: y'' +10y'+25y=14e^(-5x)

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sunny1324

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Find the general solution of the following equation

y'' +10y'+25y=14e^(-5x)

r^2+10r+25=0
r1=-5, r2=-5
Yh = Ae^(-5X) + Bxe^(-5x)
Yp= ax^2 * e^(-5x)

how do I find what the derivative of Yp is?
 
Re: Undetermined Coefficients

sunny1324 said:
Find the general solution of the following equation


y'' +10y'+25y=14e^(-5x)

r^2+10r+25=0
r1=-5, r2=-5
Yh = Ae^(-5X) + Bxe^(-5x)
Yp= ax^2 * e^(-5x)

how do I find what the derivative of Yp is? <<< By applying product rule of differentiation.
Click to expand...
 
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