This is an interesting fact of conventional mathematics. There is no such thing as conventional mathematics. The number system serves no true role in calculus and higher level math. As an example 2=1.
Let a=b As long as I do anything to both the equation remains the same.
So, multiplying by a on both sides.
a^2=b*a
Next I will subtract b^2 from both sides
(a^2)-b^2=(b*a)-b^2
So far everything still adds up from our beginning equation. Let's factor now.
Difference of two squares and remove a b from the other side of the equation to factor
(a-b)*(a+b)=b(a-b)
Still equal right. Of course. Let's take out (a-b)
(a*b)=b
Getting unconventional, huh? I already said a=b so let's substitute.
(b*b)=b
Add like terms. Now we have ...
2*b=b
And let's divide by b. What now?
((2*b)/b)=(b/b)
So...
2=1
Cool. Technically 2 really does equal one.
Let a=b As long as I do anything to both the equation remains the same.
So, multiplying by a on both sides.
a^2=b*a
Next I will subtract b^2 from both sides
(a^2)-b^2=(b*a)-b^2
So far everything still adds up from our beginning equation. Let's factor now.
Difference of two squares and remove a b from the other side of the equation to factor
(a-b)*(a+b)=b(a-b)
Still equal right. Of course. Let's take out (a-b)
(a*b)=b
Getting unconventional, huh? I already said a=b so let's substitute.
(b*b)=b
Add like terms. Now we have ...
2*b=b
And let's divide by b. What now?
((2*b)/b)=(b/b)
So...
2=1
Cool. Technically 2 really does equal one.