Type 2 word problem (linear)

linco

New member
Joined
May 23, 2010
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1
x+y=65
25x+40y=2075
I have been trying to get a straight answer on how to do this problem. I have worked a couple others correctly, but I am off on this one.
25x(65-y) =-25+25x(65-y-25)= x=40 (this is how I worked before but this is wrong)
25(40) = 1000 so 2075-1000 = 1075
I am stuck I just need to see how this is done. PLEASE
 
\(\displaystyle x+y \ = \ 65\)

\(\displaystyle 25x+40y \ = \ 2075\)

\(\displaystyle I \ assume \ that \ you \ want \ to \ solve \ the \ system.\)

\(\displaystyle Hence, \ one \ way, \ let \ y \ = \ 65-x, \ then \ by \ substitution, \ we \ have:\)

\(\displaystyle 25x+40(65-x) \ = \ 2075, \ \implies \ x \ = \ 35, \ hence \ y = 65-x \ = \ 65-35 \ = \ 30\)

\(\displaystyle I'll \ leave \ the \ check \ up \ to \ you.\)
 
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