Type 2 word problem (linear)

linco

New member
Joined
May 23, 2010
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1
x+y=65
25x+40y=2075
I have been trying to get a straight answer on how to do this problem. I have worked a couple others correctly, but I am off on this one.
25x(65-y) =-25+25x(65-y-25)= x=40 (this is how I worked before but this is wrong)
25(40) = 1000 so 2075-1000 = 1075
I am stuck I just need to see how this is done. PLEASE
 
x+y = 65\displaystyle x+y \ = \ 65

25x+40y = 2075\displaystyle 25x+40y \ = \ 2075

I assume that you want to solve the system.\displaystyle I \ assume \ that \ you \ want \ to \ solve \ the \ system.

Hence, one way, let y = 65x, then by substitution, we have:\displaystyle Hence, \ one \ way, \ let \ y \ = \ 65-x, \ then \ by \ substitution, \ we \ have:

25x+40(65x) = 2075,      x = 35, hence y=65x = 6535 = 30\displaystyle 25x+40(65-x) \ = \ 2075, \ \implies \ x \ = \ 35, \ hence \ y = 65-x \ = \ 65-35 \ = \ 30

Ill leave the check up to you.\displaystyle I'll \ leave \ the \ check \ up \ to \ you.
 
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