Hey. there are two questions that i'm trying to solve but i guess it's wrong. Thanks
1. Find the solution of the exponential equation, correct to four decimal places of 3(1+10^(6x))=5
I got 0.6901
2. Solve the equation. e^(6x)+3e^(3x)-28=0
)
I know you're supposed to solve it like a quadratic so what i did was put (e^(3x)+7)(e^(2x)-4)=0 and got x= (ln 4)/2
1. Find the solution of the exponential equation, correct to four decimal places of 3(1+10^(6x))=5
I got 0.6901
2. Solve the equation. e^(6x)+3e^(3x)-28=0
)
I know you're supposed to solve it like a quadratic so what i did was put (e^(3x)+7)(e^(2x)-4)=0 and got x= (ln 4)/2
