Two Quarter Circles in a Square, find the area of the region - any help would be appreciated, ty!

So far, I have the area of the square, the right triangle, both quarter circles, and the shape in the middle between points X and Y. I can’t find a way to get just the top part of the shape though; that’s where I’m stuck.
 
Hello4749 said:
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The area required is that bounded by \(\displaystyle ABXA\) it a sub-region of \(\displaystyle XYBX\).
The second larger region is known as a circular segment Follow that link you will a formula for its area.
The region \(\displaystyle XAYZX\) is a quarter circle. You should know its area.
The region \(\displaystyle BYZB\) is one eighth of the wlole circle. You should know its area.
The region \(\displaystyle XZB=XYZ-BYZ\)
So if you can find the area of region \(\displaystyle ABY\) and then \(\displaystyle XAYBX-AYBA\) YOU ARE DONE.

 
"WXYZ is a square" - Typically, one would keep the coordinates in a better order than that. Maybe WXZY?
"sub-region of XYBX" - Missing an intermediate destination. Maybe XAYBX?
"Area XBZ = Area XBW" - Forgot to close them. Maybe Area XBZX = Area XBWX?

Let's be careful out there!
 
I hope the example I have provided will help you to answer your question. If you have any questions don’t hesitate to ask.
 
hoosie said:
I hope the example I have provided will help you to answer your question. If you have any questions don’t hesitate to ask.
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@hoosie, Did you bother to see that this was posted in the Geometry and Trig forum ?
As such, it is inappropriate to reply with a solution that is totally dependent on knowing calculus.
 
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